MySql的join(连接)查询 (三表 left join 写法)
2017-01-11 17:51
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1、内连接:将两个表中存在连结关系的字段符合连接条件的记录形成记录集
Select A.name,B.name from A inner join B on A.id=B.id和
Select A.name,B.name from A,B where A.id=B.id结果是一样的(内连接的inner关键字可省略);
2、外连接:分为左外连接和右外连接
左连接A、B表结果包括A的全部记录和符合条件的B的记录。
右联结A、B表的结果和左联结B、A的结果是一样的,也就是说:
Select A.name,B.name from A Left Join B on A.id=B.id和
Select A.name,B.name from B Right Join A on B.id-A.id执行后的结果是一样的。
3、全联结
4、无联结
5、三表联结查询
select username,psw,gname,tel from (t1 left join t2 on t1.t1_id=t2.t1_id) left join t3 on t1.t1_id=t3.t1_id
6、终极的三表联结查询
items:商品表,item_visit_stats:商品访问表,item_trade_stats:商品销售表
SELECT i.num_iid, i.title, i.price, SUM(iv.user_visits) AS uv,it.buyer_num,it.item_num,it.item_num*i.price AS turnover
FROM (items AS i RIGHT JOIN item_visit_stats AS iv ON i.num_iid=iv.num_iid)
LEFT JOIN (SELECT num_iid,SUM(buyer_num) AS buyer_num,SUM(item_num) AS item_num FROM item_trade_stats
WHERE seller_nick="XXXX" AND business_day BETWEEN '2010-08-14' AND '2010-08-15' GROUP BY num_iid)
AS it ON it.num_iid=iv.num_iid
WHERE i.nick="XXXX" AND iv.business_day BETWEEN '2010-08-14' AND '2010-08-15'
GROUP BY i.num_iid ORDER BY uv DESC
Select A.name,B.name from A inner join B on A.id=B.id和
Select A.name,B.name from A,B where A.id=B.id结果是一样的(内连接的inner关键字可省略);
2、外连接:分为左外连接和右外连接
左连接A、B表结果包括A的全部记录和符合条件的B的记录。
右联结A、B表的结果和左联结B、A的结果是一样的,也就是说:
Select A.name,B.name from A Left Join B on A.id=B.id和
Select A.name,B.name from B Right Join A on B.id-A.id执行后的结果是一样的。
3、全联结
4、无联结
5、三表联结查询
select username,psw,gname,tel from (t1 left join t2 on t1.t1_id=t2.t1_id) left join t3 on t1.t1_id=t3.t1_id
6、终极的三表联结查询
items:商品表,item_visit_stats:商品访问表,item_trade_stats:商品销售表
SELECT i.num_iid, i.title, i.price, SUM(iv.user_visits) AS uv,it.buyer_num,it.item_num,it.item_num*i.price AS turnover
FROM (items AS i RIGHT JOIN item_visit_stats AS iv ON i.num_iid=iv.num_iid)
LEFT JOIN (SELECT num_iid,SUM(buyer_num) AS buyer_num,SUM(item_num) AS item_num FROM item_trade_stats
WHERE seller_nick="XXXX" AND business_day BETWEEN '2010-08-14' AND '2010-08-15' GROUP BY num_iid)
AS it ON it.num_iid=iv.num_iid
WHERE i.nick="XXXX" AND iv.business_day BETWEEN '2010-08-14' AND '2010-08-15'
GROUP BY i.num_iid ORDER BY uv DESC
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