237. Delete Node in a Linked List
2017-01-10 05:52
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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is
node with value
这个例子的意思是给你第三个node,让你进行操作,把list变成后面那样。要做的只是change value 和改变 next。代码如下:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public void deleteNode(ListNode node) {
node.val = node.next.val;
node.next = node.next.next;
}
}
简单的有点……奇葩……
Supposed the linked list is
1 -> 2 -> 3 -> 4and you are given the third
node with value
3, the linked list should become
1 -> 2 -> 4after calling your function.
这个例子的意思是给你第三个node,让你进行操作,把list变成后面那样。要做的只是change value 和改变 next。代码如下:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public void deleteNode(ListNode node) {
node.val = node.next.val;
node.next = node.next.next;
}
}
简单的有点……奇葩……
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