【LeetCode】 421. Maximum XOR of Two Numbers in an Array
2017-01-09 11:18
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Given a non-empty array of numbers, a0, a1,
a2, … , an-1, where 0 ≤ ai <
231.
Find the maximum result of ai XOR aj,
where 0 ≤ i, j < n.
Could you do this in O(n) runtime?
Example:
public class Solution {
public int findMaximumXOR(int[] nums) {
int max = 0, mask = 0;
for(int i = 31; i >= 0; i--){
mask = mask | (1 << i);
Set<Integer> set = new HashSet<>();
for(int num : nums){
set.add(num & mask);
}
int tmp = max | (1 << i);
for(int prefix : set){
if(set.contains(tmp ^ prefix)) {
max = tmp;
break;
}
}
}
return max;
}
}
a2, … , an-1, where 0 ≤ ai <
231.
Find the maximum result of ai XOR aj,
where 0 ≤ i, j < n.
Could you do this in O(n) runtime?
Example:
Input: [3, 10, 5, 25, 2, 8] Output: 28 Explanation: The maximum result is 5 ^ 25 = 28.
public class Solution {
public int findMaximumXOR(int[] nums) {
int max = 0, mask = 0;
for(int i = 31; i >= 0; i--){
mask = mask | (1 << i);
Set<Integer> set = new HashSet<>();
for(int num : nums){
set.add(num & mask);
}
int tmp = max | (1 << i);
for(int prefix : set){
if(set.contains(tmp ^ prefix)) {
max = tmp;
break;
}
}
}
return max;
}
}
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