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461. Hamming Distance 难度:easy

2017-01-08 20:53 267 查看
题目:

The Hamming distance between two integers is the number of positions at which the corresponding
bits are different.

Given two integers 
x
 and 
y
,
calculate the Hamming distance.

Note:

0 ≤ 
x
y
 <
231.

Example:
Input: x = 1, y = 4

Output: 2

Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
↑   ↑

The above arrows point to positions where the corresponding bits are different.


程序:

class Solution {
public:
int hammingDistance(int x, int y) {
int temp = x ^ y;
int count = 0;
while(temp)
{
count += (temp % 2);
temp /= 2;
}
return count;
}
};
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