您的位置:首页 > 其它

【LeetCode】 442. Find All Duplicates in an Array

2017-01-06 08:54 204 查看
Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once.

Find all the elements that appear twice in this array.

Could you do it without extra space and in O(n) runtime?

Example:

Input:
[4,3,2,7,8,2,3,1]

Output:
[2,3]


public class Solution {
public List<Integer> findDuplicates(int[] nums) {
List<Integer> res = new ArrayList<>();
for (int i = 0; i < nums.length; i++) {
int index = Math.abs(nums[i]) - 1;
if (nums[index] < 0) {
res.add(Math.abs(index + 1));
} else {
nums[index] = -nums[index];
}
}
return res;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: