[LeetCode]453. Minimum Moves to Equal Array Elements
2017-01-04 23:51
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Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
Input:
[1,2,3]
Output:
3
Explanation:
Only three moves are needed (remember each move increments two elements):
[1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
题目链接: https://leetcode.com/problems/minimum-moves-to-equal-array-elements/
解题思路:设最小的数为Min,数组的和为Sum,设最小值增加X次为最后相等的值,可得方程
(Min+x)∗n=(n−1)∗x+Sum
可解得 X=Sum−Min∗n
Example:
Input:
[1,2,3]
Output:
3
Explanation:
Only three moves are needed (remember each move increments two elements):
[1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
题目链接: https://leetcode.com/problems/minimum-moves-to-equal-array-elements/
解题思路:设最小的数为Min,数组的和为Sum,设最小值增加X次为最后相等的值,可得方程
(Min+x)∗n=(n−1)∗x+Sum
可解得 X=Sum−Min∗n
class Solution { public: int minMoves(vector<int>& nums) { int n=nums.size(); int sum=0,minn=INT_MAX ; for(int i=0;i<n;i++){ sum+=nums[i]; minn=min(minn,nums[i]); } return sum-minn*n; } };
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