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关于Android定位获取详细地址的问题

2017-01-02 13:26 435 查看
遇到的问题是:运行在不同的手机上显示的地址不同,当然经纬度是一样的。请教各位大神,这是什么原因?

private Location getLocation(Context context){

        LocationManager manager = (LocationManager) context.getSystemService(context.LOCATION_SERVICE);

        //若GPS未开启

        if(!manager.isProviderEnabled(LocationManager.GPS_PROVIDER)){

            Toast.makeText(SigninActivity.this, "请开启GPS!", Toast.LENGTH_SHORT).show();

            Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);

            SigninActivity.this.startActivityForResult(intent, 0); //此为设置完成后返回到获取界面

        }

        //获得GPS支持

        location = manager.getLastKnownLocation(LocationManager.GPS_PROVIDER);

        Log.v("location1", location + "");

        if (location == null){

            //获得PASSIVE支持

            location = manager.getLastKnownLocation(LocationManager.PASSIVE_PROVIDER);

            Log.v("location2",location+"");

        }else {

            //获得NETWORK支持

            location = manager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

            Log.v("location3",location+"");

        }

        geocoder = new Geocoder(SigninActivity.this);

        try {

            List<Address> list = geocoder.getFromLocation(location.getLatitude(),location.getLongitude(),5);

            Log.v("location",location.getLatitude()+","+location.getLongitude());

            if (list != null){

                for (int i=0; i<list.size(); i++){

                    Address address = list.get(i);

                    String add="";

                    int maxLine = address.getMaxAddressLineIndex();

                    Log.v("maxline",maxLine+"");

                    if (maxLine >= 2) {

                        add = address.getAddressLine(1) + address.getAddressLine(2);

                    } else {

                        add = address.getAddressLine(1);

                    }

                    tv_locaion.setText(add);

                }

            }

        } catch (IOException e) {

            e.printStackTrace();

        }

        return  location;

    }
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