LeetCode455. Assign Cookies简单的做法
2016-12-31 11:28
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Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi,
which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >=
gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and
output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Example 2:
Solution:
class Solution {
public:
int findContentChildren(vector<int>& g, vector<int>& s) {
std::sort(g.begin(), g.end());
std::sort(s.begin(), s.end());
int idx = 0;
int count = 0;
for (int i = 0; i < g.size(); ++i) {
while (true) {
if (idx >= s.size()) {
goto result;
}
if (s[idx++] >= g[i]) {
count++;
break;
}
}
}
result:
return count;
}
};
which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >=
gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and
output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Input: [1,2,3], [1,1] Output: 1 Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content. You need to output 1.
Example 2:
Input: [1,2], [1,2,3] Output: 2 Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. You have 3 cookies and their sizes are big enough to gratify all of the children, You need to output 2.
Solution:
class Solution {
public:
int findContentChildren(vector<int>& g, vector<int>& s) {
std::sort(g.begin(), g.end());
std::sort(s.begin(), s.end());
int idx = 0;
int count = 0;
for (int i = 0; i < g.size(); ++i) {
while (true) {
if (idx >= s.size()) {
goto result;
}
if (s[idx++] >= g[i]) {
count++;
break;
}
}
}
result:
return count;
}
};
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