Codeforces 749C-voting
2016-12-28 22:12
393 查看
Voting
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
There are n employees in Alternative Cake Manufacturing (ACM). They are now voting on some very important question and the leading
world media are trying to predict the outcome of the vote.
Each of the employees belongs to one of two fractions: depublicans or remocrats, and these two fractions have opposite opinions on what should be the outcome of the vote. The voting procedure is rather complicated:
Each of n employees makes a statement. They make statements one by one starting from employees 1 and
finishing with employee n. If at the moment when it's time for the i-th
employee to make a statement he no longer has the right to vote, he just skips his turn (and no longer takes part in this voting).
When employee makes a statement, he can do nothing or declare that one of the other employees no longer has a right to vote. It's allowed to deny from voting people who already made the statement or people who are only waiting to do so. If someone is denied
from voting he no longer participates in the voting till the very end.
When all employees are done with their statements, the procedure repeats: again, each employees starting from 1 and finishing with n who
are still eligible to vote make their statements.
The process repeats until there is only one employee eligible to vote remaining and he determines the outcome of the whole voting. Of course, he votes for the decision suitable for his fraction.
You know the order employees are going to vote and that they behave optimal (and they also know the order and who belongs to which fraction). Predict the outcome of the vote.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) —
the number of employees.
The next line contains n characters. The i-th
character is 'D' if the i-th
employee is from depublicans fraction or 'R' if he is from remocrats.
Output
Print 'D' if the outcome of the vote will be suitable for depublicans and 'R'
if remocrats will win.
Examples
input
output
input
output
Note
Consider one of the voting scenarios for the first sample:
Employee 1 denies employee 5 to
vote.
Employee 2 denies employee 3 to
vote.
Employee 3 has no right to vote and skips his turn (he was denied by employee 2).
Employee 4 denies employee 2 to
vote.
Employee 5 has no right to vote and skips his turn (he was denied by employee 1).
Employee 1 denies employee 4.
Only employee 1 now has the right to vote so the voting ends with the victory of depublicans.
题意:有n个人投票,分为 D 和 R 两派,从1~n的顺序投票,轮到某人投票的时候,他可以将对方的一个人KO,被KO的人不能投票了,这样循环,直到某一派的人全部被KO,问哪方赢。
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
#include <vector>
#include <set>
using namespace std;
#define LL long long
char ch[200600];
int visit[200009];
int main()
{
int n;
while(~scanf("%d",&n))
{
memset(visit,0,sizeof(visit));
scanf("%s",ch);
queue<int>q1;
queue<int>q2;
for(int i=0; i<n; i++)
{
if(ch[i]=='D') q1.push(i);
else q2.push(i);
}
while(q1.size()&&q2.size())
{
for(int i=0; i<n; i++)
{
if(visit[i]==1) continue;
if(ch[i]=='D')
{
int a=q1.front();
q1.pop();
q1.push(a);
int b=q2.front();
visit[b]=1;
q2.pop();
}
else
{
int a=q2.front();
q2.pop();
q2.push(a);
int b=q1.front();
visit[b]=1;
q1.pop();
}
if(q1.size()==0||q2.size()==0) break;
}
if(q1.size()==0||q2.size()==0) break;
}
if(q1.size()==0) printf("R\n");
else printf("D\n");
}
return 0;
}
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
There are n employees in Alternative Cake Manufacturing (ACM). They are now voting on some very important question and the leading
world media are trying to predict the outcome of the vote.
Each of the employees belongs to one of two fractions: depublicans or remocrats, and these two fractions have opposite opinions on what should be the outcome of the vote. The voting procedure is rather complicated:
Each of n employees makes a statement. They make statements one by one starting from employees 1 and
finishing with employee n. If at the moment when it's time for the i-th
employee to make a statement he no longer has the right to vote, he just skips his turn (and no longer takes part in this voting).
When employee makes a statement, he can do nothing or declare that one of the other employees no longer has a right to vote. It's allowed to deny from voting people who already made the statement or people who are only waiting to do so. If someone is denied
from voting he no longer participates in the voting till the very end.
When all employees are done with their statements, the procedure repeats: again, each employees starting from 1 and finishing with n who
are still eligible to vote make their statements.
The process repeats until there is only one employee eligible to vote remaining and he determines the outcome of the whole voting. Of course, he votes for the decision suitable for his fraction.
You know the order employees are going to vote and that they behave optimal (and they also know the order and who belongs to which fraction). Predict the outcome of the vote.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) —
the number of employees.
The next line contains n characters. The i-th
character is 'D' if the i-th
employee is from depublicans fraction or 'R' if he is from remocrats.
Output
Print 'D' if the outcome of the vote will be suitable for depublicans and 'R'
if remocrats will win.
Examples
input
5 DDRRR
output
D
input
6 DDRRRR
output
R
Note
Consider one of the voting scenarios for the first sample:
Employee 1 denies employee 5 to
vote.
Employee 2 denies employee 3 to
vote.
Employee 3 has no right to vote and skips his turn (he was denied by employee 2).
Employee 4 denies employee 2 to
vote.
Employee 5 has no right to vote and skips his turn (he was denied by employee 1).
Employee 1 denies employee 4.
Only employee 1 now has the right to vote so the voting ends with the victory of depublicans.
题意:有n个人投票,分为 D 和 R 两派,从1~n的顺序投票,轮到某人投票的时候,他可以将对方的一个人KO,被KO的人不能投票了,这样循环,直到某一派的人全部被KO,问哪方赢。
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
#include <vector>
#include <set>
using namespace std;
#define LL long long
char ch[200600];
int visit[200009];
int main()
{
int n;
while(~scanf("%d",&n))
{
memset(visit,0,sizeof(visit));
scanf("%s",ch);
queue<int>q1;
queue<int>q2;
for(int i=0; i<n; i++)
{
if(ch[i]=='D') q1.push(i);
else q2.push(i);
}
while(q1.size()&&q2.size())
{
for(int i=0; i<n; i++)
{
if(visit[i]==1) continue;
if(ch[i]=='D')
{
int a=q1.front();
q1.pop();
q1.push(a);
int b=q2.front();
visit[b]=1;
q2.pop();
}
else
{
int a=q2.front();
q2.pop();
q2.push(a);
int b=q1.front();
visit[b]=1;
q1.pop();
}
if(q1.size()==0||q2.size()==0) break;
}
if(q1.size()==0||q2.size()==0) break;
}
if(q1.size()==0) printf("R\n");
else printf("D\n");
}
return 0;
}
相关文章推荐
- Codeforces 749C Voting 贪心+模拟
- 【codeforces 749C】 Voting
- 【 codeforces 749C 】 Voting
- 【 codeforces 749C 】 Voting
- 【 codeforces 749C 】 Voting
- codeforces 749C Voting
- Codeforces 637A Voting for Photos 【水题】
- CodeForces 637 A.Voting for Photos(水~)
- codeforces 637A A. Voting for Photos(水题)
- Codeforces 749C【模拟】
- codeforces 388 C Voting
- Codeforces Round #388 (Div. 2) 749C Voting
- codeforces div2 round388 D Voting 线段树
- CodeForces 526A-Voting for Photos【模拟】
- codeforces 490D Chocolate 数论
- Codeforces 67C Sequence of Balls 编辑距离 dp
- Codeforces 274A:k-Multiple Free Set(初识set集合)
- codeforces 766 C Mahmoud and a Message [基础DP]【动态规划】
- CodeForces 834A The Useless Toy
- 【解题报告】Tree Destruction CodeForces - 911F(搜索??)