【LeetCode】 016. 3Sum Closest
2016-12-28 12:26
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Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have
exactly one solution.
public class Solution {
public int threeSumClosest(int[] nums, int target) {
Arrays.sort(nums);
int res = nums[0] + nums[1] + nums[2];
for (int i = 0; i < nums.length - 2; i++) {
int start = i + 1, end = nums.length - 1;
while (start < end) {
int sum = nums[i] + nums[start] + nums[end];
if (sum < target) {
start++;
} else {
end--;
}
if (Math.abs(sum - target) < Math.abs(res - target)) {
res = sum;
}
}
}
return res;
}
}
exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
public class Solution {
public int threeSumClosest(int[] nums, int target) {
Arrays.sort(nums);
int res = nums[0] + nums[1] + nums[2];
for (int i = 0; i < nums.length - 2; i++) {
int start = i + 1, end = nums.length - 1;
while (start < end) {
int sum = nums[i] + nums[start] + nums[end];
if (sum < target) {
start++;
} else {
end--;
}
if (Math.abs(sum - target) < Math.abs(res - target)) {
res = sum;
}
}
}
return res;
}
}
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