【leetcode】88. Merge Sorted Array【java】
2016-12-26 15:09
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Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
从后往前依次将较大的元素放入数组中。
public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i = m - 1;
int j = n - 1;
int index = m + n - 1;
while (i >= 0 && j >= 0){
if (nums1[i] > nums2[j]){
nums1[index] = nums1[i];
index--;
i--;
} else {
nums1[index] = nums2[j];
index--;
j--;
}
}
while (i >= 0){
nums1[index] = nums1[i];
index--;
i--;
}
while (j >= 0){
nums1[index] = nums2[j];
index--;
j--;
}
}
}
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
从后往前依次将较大的元素放入数组中。
public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i = m - 1;
int j = n - 1;
int index = m + n - 1;
while (i >= 0 && j >= 0){
if (nums1[i] > nums2[j]){
nums1[index] = nums1[i];
index--;
i--;
} else {
nums1[index] = nums2[j];
index--;
j--;
}
}
while (i >= 0){
nums1[index] = nums1[i];
index--;
i--;
}
while (j >= 0){
nums1[index] = nums2[j];
index--;
j--;
}
}
}
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