【LeetCode】 383. Ransom Note
2016-12-25 00:09
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Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
public class Solution {
public boolean canConstruct(String ransomNote, String magazine) {
int[] charArray = new int[26];
for (char c : magazine.toCharArray()) {
charArray[c - 'a']++;
}
for (char c : ransomNote.toCharArray()) {
if (--charArray[c - 'a'] < 0) {
return false;
}
}
return true;
}
}
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false canConstruct("aa", "ab") -> false canConstruct("aa", "aab") -> true
public class Solution {
public boolean canConstruct(String ransomNote, String magazine) {
int[] charArray = new int[26];
for (char c : magazine.toCharArray()) {
charArray[c - 'a']++;
}
for (char c : ransomNote.toCharArray()) {
if (--charArray[c - 'a'] < 0) {
return false;
}
}
return true;
}
}
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