实现蛇形输出

实现如下的蛇形输出：

1 2 3 4 5

16 17 18 19 6

15 24 25 20 7

14 23 22 21 8

13 12 11 10 9

具体代码实现：

[html] view
plain copy







#include <stdio.h>

#include <malloc.h>

int main()

{

int n;

int x,y,round;

//a[x][y]，x是二维数组的第一个下标，y是二维数组的第二个下标，

//round是转的圈数，从0开始。

int count = 1;//从1开始计数

printf("Please input a number:\n");

scanf("%d",&n);//用户输入n的值

int (*a)
= calloc(n * n,sizeof(int));//创建n*n的矩阵

for(round = 0; round < n / 2; round++)

{

x = round;

for(y = round; y < n - round; y++)

{

a[x][y] = count;

count++;

}

//print 1,2,3,4,5

y = n - round - 1;

for(x = round + 1; x < n - round - 1; x++)

{

a[x][y] = count;

count++;

}

//print 6,7,8

x = n - round - 1;

for(y = n - round - 1; y >= round; y--)

{

a[x][y] = count;

count++;

}

//print 13,12,11,10,9

y = round;

for(x = n - round - 2; x > round; x--)

{

a[x][y] = count;

count++;

}

//print 16,15,14

}

if(n % 2 == 1)

{

a[n / 2][n / 2] = n * n;

}

for(x = 0 ; x < n; x++)

{

for(y = 0; y < n; y++)

{

printf(" %d ",a[x][y]);

}

printf("\n");

}

free(a);

return 0;

}