剑指offer——面试题42：翻转单词顺序VS左旋转字符串

void Reverse(char *pBegin, char *pEnd)
{
if(pBegin == NULL || pEnd == NULL)
return;

while(pBegin < pEnd)
{
char temp = *pBegin;
*pBegin = *pEnd;
*pEnd = temp;

pBegin ++, pEnd --;
}
}



char* ReverseSentence(char *pData)
{
if(pData == NULL)
return NULL;

char *pBegin = pData;

char *pEnd = pData;
while(*pEnd != '\0')
pEnd ++;
pEnd--;

// 翻转整个句子
Reverse(pBegin, pEnd);

// 翻转句子中的每个单词
pBegin = pEnd = pData;
while(*pBegin != '\0')
{
if(*pBegin == ' ')
{
pBegin ++;
pEnd ++;
}
else if(*pEnd == ' ' || *pEnd == '\0')
{
Reverse(pBegin, --pEnd);
pBegin = ++pEnd;
}
else
{
pEnd ++;
}
}

return pData;
}







char* LeftRotateString(char* pStr, int n)
{
if(pStr != NULL)
{
int nLength = static_cast<int>(strlen(pStr));
if(nLength > 0 && n > 0 && n < nLength)
{
char* pFirstStart = pStr;
char* pFirstEnd = pStr + n - 1;
char* pSecondStart = pStr + n;
char* pSecondEnd = pStr + nLength - 1;

// 翻转字符串的前面n个字符
Reverse(pFirstStart, pFirstEnd);
// 翻转字符串的后面部分
Reverse(pSecondStart, pSecondEnd);
// 翻转整个字符串
Reverse(pFirstStart, pSecondEnd);
}
}

return pStr;
}