删除一个字符串中出现次数最少的字符

【输入】s为输入字符串，Len为输入字符串长度 

如输入字符串为“abcdd”，输出为”dd” 

字符串中只有小写字母，不含空格且字符串最大长度不超过20 

下面贴出程序和想法： 

1、第一是如果遇到大于最小字母个数的字母直接存储到字符串中，这样就可以删除字符了。

#include <stdio.h>
#include <string.h>

char *deClear(char *str,int len)
{
int i;
int minnum;
int count[26] = {0};
static char pstr[100];

for(i = 0; i < len; i++)
{
count[str[i] - 'a']++;
}
for( i = 0; i < len; i++)
{
if(count[i] != 0)
{
minnum = count[i];
}
}
for(i = 0; i < len; i++)
{
if(count[i] < minum && count[i] != 0)
{
minnum = count[i];
}
}

for(i = 0; i < len; i++)
{
if(count[str[i] - 'a'] > minnum)
{
pstr[n++] = str[i];
}
pstr
= '\0';
}
return pstr;

}

int main()

{
char str[100];
int count[26] = {0};
printf("please input the string.h\n");
scanf("%s",str);

int len = strlen(str);
deClear(str,count,len）；
printf("the result is %s\n",str);

reuturn 0;
}

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2、直接处理最小的字母。

#include <stdio.h>

void delete_ch(char *str);
{
int i;
int len = strlen(str）；
for(i = 0; i < len; i++)
{
*(str + i) = *(str + i + 1);
}
*(str + len - 1) = '\0';
}

void get_count_ch（int *count,char *str)
{
int i = 0;
int len = strlen(str);
for(i = 0; i < len; i++)
{
count[*(str +i ) - 'a']++;
}
}
int get_min_count_ch(int *count)
{
int i;
int minnum;
for（i = 0； i < 26; i++)
{
if(count[i] != 0)
{
minnum = count[i];
for(; i < 26; i++)
{
if(count[i] < minnum && count[i] != '\0')
{
minnum = count[i];
}
}
}
}

return minnum;

}

void delete_min_count_ch(char *str,int minnum);
{
while(*str != '\0')
{
if(count[*str - 'a'] == minnum)
{
delete_ch(str);
}
else
{
str++;
}
}
}
int main()
{
char str[100];
int count[26] = {0};

printf("please input the string:\n");
scanf("%s",str);

int len = strlen(str);
get_count_ch(count,str,len);
int min = get_min_count_ch(count);
delete_min_count_ch(str,min);

printf("the result is %s\n",str);

return 0;
}