[LeetCode]Sum Root to Leaf Numbers
2016-11-26 17:16
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Question
Given a binary tree containing digits from
An example is the root-to-leaf path
Find the total sum of all root-to-leaf numbers.
For example,
The root-to-leaf path
The root-to-leaf path
Return the sum = 12 + 13 =
本题难度Medium。
DFS
【复杂度】
时间 O(N) 空间 O(1)
【思路】
这道题并不难,从上而下地进行递推累加,然后返回其累加值。
【注意】
叶子节点是其左右子树都为null。只有一个子树为null的不是叶子节点!
【代码】
Given a binary tree containing digits from
0-9only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path
1->2->3which represents the number
123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path
1->2represents the number
12.
The root-to-leaf path
1->3represents the number
13.
Return the sum = 12 + 13 =
25.
本题难度Medium。
DFS
【复杂度】
时间 O(N) 空间 O(1)
【思路】
这道题并不难,从上而下地进行递推累加,然后返回其累加值。
【注意】
叶子节点是其左右子树都为null。只有一个子树为null的不是叶子节点!
【代码】
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public int sumNumbers(TreeNode root) { //invariant return helper(root,0); } private int helper(TreeNode root,int pre){ //base case if(root==null) return 0; if(root.left==null&&root.right==null) return pre*10+root.val; return helper(root.left,pre*10+root.val)+helper(root.right,pre*10+root.val); } }
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