HDU1039 Easier Done Than Said?

/*
题目大意：验证所设密码可否接受，要求满足以下三个条件：
1、必须包含元音
2、三个连续的字母不能同时为元音或者辅音
3、两个连续的字母不能相同，其中"ee"."oo"除外
*/

#include <bits/stdc++.h>
using namespace std;

int main() {
string s;
while (cin >> s && s != "end") {
int flag = 0;
int p = s.size();
for (int i = 0; i<p; i++) {
if (s[i] == 'a' || s[i] == 'e' || s[i] == 'i' || s[i] == 'o' || s[i] == 'u')    flag = 1;
}
int flag1 = 0;
for (int i = 2; i<p; i++) {
if ((s[i] == 'a' || s[i] == 'e' || s[i] == 'i' || s[i] == 'o' || s[i] == 'u') && ((s[i-1] == 'a' || s[i-1] == 'e' || s[i-1] == 'i' || s[i-1] == 'o' || s[i-1] == 'u')) && (s[i-2] == 'a' || s[i-2] == 'e' || s[i-2] == 'i' || s[i-2] == 'o' || s[i-2] == 'u'))
flag1 = 1;
else if ((s[i] != 'a' && s[i] != 'e' && s[i] != 'i' && s[i] != 'o' && s[i] != 'u') && ((s[i-1] != 'a' && s[i-1] != 'e' && s[i-1] != 'i' && s[i-1] != 'o' && s[i-1] != 'u')) && (s[i-2] != 'a' && s[i-2] != 'e' && s[i-2] != 'i' && s[i-2] != 'o' && s[i-2] != 'u'))
flag1 = 1;
}
int flag2 = 0;
for (int i = 1; i<p; i++) {
if (s[i] == s[i-1] && (s[i] != 'e'&& s[i] != 'o')) flag2 = 1;
}
//cout << flag << flag1 <<flag2 <<endl;
if (flag == 1 && flag1 == 0 && flag2 == 0)  cout << "<" << s << ">" << " is acceptable." << endl;
else    cout << "<" << s << ">" << " is not acceptable." << endl;
s = "";
}
return 0;
}