POJ 2559 Largest Rectangle in a Histogram 单调栈
2016-11-25 19:09
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题目:
http://poj.org/problem?id=2559题意:
给定一个直方图,求直方图中能包含的最大的矩形面积思路:
跟hdu 1506是一个题,不同的是用了不一样的做法。用单调栈求此点之前第一个值小于此点的位置,和此点之后第一个值小于此点的位置,巧妙#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; typedef long long ll; const int N = 100010; int arr , st , l , r ; int main() { int n; while(scanf("%d", &n), n) { for(int i = 1; i <= n; i++) scanf("%d", &arr[i]); int k = 0; for(int i = 1; i <= n; i++) { while(k > 0 && arr[st[k-1]] >= arr[i]) k--; if(k == 0) l[i] = 1; else l[i] = st[k-1] + 1; st[k++] = i; } k = 0; for(int i = n; i >= 1; i--) { while(k > 0 && arr[st[k-1]] >= arr[i]) k--; if(k == 0) r[i] = n; else r[i] = st[k-1] - 1; st[k++] = i; } ll res = -1; for(int i = 1; i <= n; i++) res = max(res, (ll)arr[i] * (r[i] - l[i] + 1)); printf("%lld\n", res); } return 0; }
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