您的位置:首页 > 其它

LeetCode 437. Path Sum III

2016-11-12 11:24 555 查看

Problem Statement

(Source) You are given a binary tree in which each node contains an integer value.

Find the number of paths that sum to a given value.

The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).

The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.

Example:

root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8

10
/  \
5   -3
/ \    \
3   2   11
/ \   \
3  -2   1

Return 3. The paths that sum to 8 are:

1.  5 -> 3
2.  5 -> 2 -> 1
3. -3 -> 11


Tags:
Tree
.

Solution

Idea:
TODO
.

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
def pathSum(self, root, sum):
"""
:type root: TreeNode
:type sum: int
:rtype: int
"""
prefix_sum = {0 : 1}
return self.helper(root, sum, prefix_sum, 0)

def helper(self, root, target, prefix_sum, cur):
if not root: return 0
total = cur + root.val
res = prefix_sum.get(total - target, 0)
prefix_sum[total] = prefix_sum.get(total, 0) + 1
res += self.helper(root.left, target, prefix_sum, total) + \
self.helper(root.right, target, prefix_sum, total)
prefix_sum[total] -= 1
return res


Complexity Analysis:

Time Complexity: O(n).

Space Complexity: ?.
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: