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LeetCode #104 - Maximum Depth of Binary Tree - Easy

2016-11-07 21:40 417 查看

Problem

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.


Example

1
/  \
2   2
\   \
3    3

maximum depth = 3


Algorithm

整理一下题意:给定一个二叉树,要求返回其最大深度

本题比较简单,直接通过DFS,每次返回子树的最大深度加一即可得到。代码如下。

//DFS,
/**
* Definition for a binary tree node.
* struct TreeNode {
*     int val;
*     TreeNode *left;
*     TreeNode *right;
*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int maxDepth(TreeNode* root) {
if(root==NULL) return 0;
return 1+max(maxDepth(root->left),maxDepth(root->right));
}
};
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