Opencv绘制直方图及创建按钮遇到的问题

创建按钮，总是报错，一开始是报错缺少QT支持，后来创建QT Application程序编译不报错，运行时会

下面是单独实现绘制直方图代码，解决上面方法的方案，求大神知道

#include "testqt_1101.h"

#include <QtWidgets/QApplication>

#include <opencv2\core\utility.hpp>

#include <opencv2\imgproc.hpp>

#include <opencv2\highgui.hpp>

#include <iostream>

using namespace std;

using namespace cv;

Mat img= imread("C:\\Users\\hasee\\Desktop\\cat2.jpg");

void showHistoCallback(int state, void* userData);

void equlizeCallback(int state, void* userData);

int main()

{
vector<Mat> bgr;
split(img, bgr);
int numbins = 256;
float range[] = { 0,256 };
const float* histRange = { range };
Mat b_hist, g_hist, r_hist;
calcHist(&bgr[0], 1, 0, Mat(), b_hist, 1, &numbins, &histRange);
calcHist(&bgr[1], 1, 0, Mat(), g_hist, 1, &numbins, &histRange);
calcHist(&bgr[2], 1, 0, Mat(), r_hist, 1, &numbins, &histRange);
int width = 512;
int height = 300;

Mat histImage(height, width, CV_8UC3, Scalar(20, 20, 20));

normalize(b_hist, b_hist, 0, height, NORM_MINMAX);
normalize(g_hist, g_hist, 0, height, NORM_MINMAX);
normalize(r_hist, r_hist, 0, height, NORM_MINMAX);

int binStep = cvRound((float)width / (float)numbins);

for (int i = 1; i < numbins; i++)
{
line(histImage,
Point(binStep*(i - 1), height - cvRound(b_hist.at<float>(i - 1))),
Point(binStep*(i), height - cvRound(b_hist.at<float>(i))),
Scalar(255, 0, 0));
line(histImage,
Point(binStep*(i - 1), height - cvRound(g_hist.at<float>(i - 1))),
Point(binStep*(i), height - cvRound(g_hist.at<float>(i))),
Scalar(0, 255, 0));
line(histImage,
Point(binStep*(i - 1), height - cvRound(r_hist.at<float>(i - 1))),
Point(binStep*(i), height - cvRound(r_hist.at<float>(i))),
Scalar(0, 0, 255));
}
imshow("直方图", histImage);
   //namedWindow("Input");

  //createButton("ss", showHistoCallback, NULL, QT_PUSH_BUTTON, 0);
//createButton("直方图均衡化",equlizeCallback,NULL,QT_PUSH_BUTTON,0);
//imshow("Input", img);*/
waitKey(0);
return 0;

}