103. Binary Tree Zigzag Level Order Traversal
2016-11-04 21:56
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这道题可以借鉴102的层序遍历,再加一个变量计算树的层数,如果为偶数则翻转。
class Solution { public: vector<vector<int>> zigzagLevelOrder(TreeNode* root) { vector<vector<int> >ret; if(!root) return ret; queue<TreeNode*>qtree; qtree.push(root); qtree.push(NULL); int count=1; vector<int>num; while(!qtree.empty()) { TreeNode*temp=qtree.front(); qtree.pop(); if(temp==NULL) { if(count%2==0) reverse(num.begin(),num.end()); ret.push_back(num); num.clear(); if(qtree.size()>0) { count++; qtree.push(NULL); } else break; } else { num.push_back(temp->val); if(temp->left) qtree.push(temp->left); if(temp->right) qtree.push(temp->right); } } return ret; } };
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