1058. A+B in Hogwarts (20)
2016-11-04 00:19
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If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of “Galleon.Sickle.Knut” (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
就是一个进制的问题.
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
就是一个进制的问题.
#include <iostream> using namespace std; struct Num { int a; int b; int c; }; int main() { Num n1, n2, n3; scanf("%d.%d.%d", &n1.a, &n1.b, &n1.c); scanf("%d.%d.%d", &n2.a, &n2.b, &n2.c); int flag = 0; int temp = n1.c + n2.c; if (temp >= 29) { flag = 1; n3.c = temp - 29; } else { n3.c = temp; } temp = n1.b + n2.b + flag; if (temp >= 17) { n3.b = temp - 17; flag = 1; } else { n3.b = temp; flag = 0; } n3.a = n1.a + n2.a + flag; printf("%d.%d.%d", n3.a, n3.b, n3.c); return 0; }
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