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codeforces 733D (水题)

2016-11-03 21:13 309 查看

题目链接:点击这里

题意:给出n个长方体,两个长方体如果有一个面完全一样就能拼起来,或者只选择一个。求一个最佳的方案使得内接球直径最大。

直接暴力把所有的面扔进一个数组,排序之后找到第三条边最大的,维护一下最大值就好了。

#include <cmath>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <vector>
#include <cstdio>
using namespace std;
#define maxn 600005

struct node {
long long x, y, z;
int id;
bool operator < (const node &a) const {
if (x != a.x) return x < a.x;
if (y != a.y) return y < a.y;
if (z != a.z) return z < a.z;
return id < a.id;
}
}a[maxn];
int gg[maxn][3];

int dp[maxn][22], n;
void rmq_init () {
for (int i = 0; i < n; i++) dp[i][0] = a[i].z;
for (int j = 1; (1<<j) <= n; j++) {
for (int i = 0; i+(1<<j)-1 < n; i++) {
dp[i][j] = max (dp[i][j-1], dp[i+(1<<(j-1))][j-1]);
}
}
}

int rmq (int l, int r) {
int k = 0;
while ((1<<(k+1)) <= r-l+1) k++;
return max (dp[l][k], dp[r-(1<<k)+1][k]);
}

int main () {
scanf ("%d", &n);
int tmp = 0, pos = 0;
int cnt = 0;
for (int i = 1; i <= n; i++) {
int x, y, z; scanf ("%d%d%d", &x, &y, &z);
if (min (x, min (y, z)) > tmp) {
tmp = min (x, min (y, z));
pos = i;
}
gg[i][0] = x, gg[i][1] = y, gg[i][2] = z;
a[cnt++] = ((node) {x, y, z, i});
a[cnt++] = ((node) {x, z, y, i});
a[cnt++] = ((node) {y, x, z, i});
a[cnt++] = ((node) {y, z, x, i});
a[cnt++] = ((node) {z, x, y, i});
a[cnt++] = ((node) {z, y, x, i});
}
n *= 6;
sort (a, a+n);
int ans = 0, p1 = 0, p2 = 0;
for (int i = 0; i < n; i++) {
node now = a[i]; now.y = a[i].y+1; now.id = now.z = 0;
int pos = lower_bound (a+i+1, a+n, now)-a-1;
if (a[pos].id == a[i].id || pos <= i) continue;
int tmp = min (min (a[i].x, a[i].y), a[i].z+a[pos].z);
if (tmp > ans) {
ans = tmp;
p1 = a[i].id;
p2 = a[pos].id;
}
}
if (tmp > ans) {
printf ("1\n%d\n", pos);
}
else {
printf ("2\n%d %d\n", min (p1, p2), max (p1, p2));
}
return 0;
}
/*
2
6 10 10
10 10 6
*/
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