223. Rectangle Area （求两矩形重合部分的面积）

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.



Assume that the total area is never beyond the maximum possible value of int.
public class Solution {
public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int sub = 0;
if(A>=G||E>=C||B>=H||F>=D)
sub = 0;
else{
int length1 = 0,length2=0;
if(H<D){
if(B>F)
length1=H-B;
else
length1=H-F;
}
else{
if(F>B)
length1=D-F;
else
length1=D-B;
}
if(A<E){
if(C<G)
length2=C-E;
else
length2=G-E;
}
else{
if(C>G)
length2=G-A;
else
length2=C-A;
}
sub = length1*length2;
}
return (D-B)*(C-A)+(G-E)*(H-F)-sub;
}
}