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栈的应用之进制转换

2016-10-23 21:37 155 查看
利用栈的后进先出性质写一个10到8进制转换的小程序,数组方式实现栈,代码如下:

#include<stdio.h>
#include<stdlib.h>
#define stack_size 100
#define stack_crement_size 10
typedef int Elemtype;

///////////////////声明一个栈
typedef struct Stack
{
Elemtype *top;
Elemtype *base;
int stacksize;
}sqstack;

//函数声明
void IntiStack(sqstack *s);
int Push(sqstack* s,Elemtype e);
void Pop(sqstack* s,Elemtype *e);
int StackLen(sqstack s);
int StackEmpty(sqstack* s);
void DestoryStack(sqstack* s);

/////////////////初始化栈
void IntiStack(sqstack *s)
{
s->base = (Elemtype*)malloc(sizeof(Elemtype)*stack_size);
if(!s->base)
exit(0);

s->top = s->base;                 //设置栈为空
s->stacksize = stack_size;
}

/////////////////入栈操作
int Push(sqstack* s,Elemtype e)
{
if(s->top - s->base >= s->stacksize)    //判断是否栈满
{
s->base = (Elemtype*)realloc(s->base,(s->stacksize + stack_crement_size)*sizeof(Elemtype));
if(!s->base)
exit(0);

s->top = s->base + s->stacksize;                                   //重新设置栈顶
s->stacksize += stack_crement_size;                                //重新设置栈的大小
}

*(s->top) = e;
s->top++;

return 1;
}

/////////////////出栈操作
void Pop(sqstack* s,Elemtype *e)
{
if(s->top == s->base)                                                //如果栈为空
return;

*e = *--(s->top);
}

/////////////////求栈的当前容量
int StackLen(sqstack s)
{
return s.top - s.base;
}

/////////////////清空栈
int StackEmpty(sqstack* s)
{
return (s->stacksize == 0);
}
/////////////////销毁栈
void DestoryStack(sqstack* s)
{
int i,len;
len = s->stacksize;

for( i = 0; i <len; i++)
{
s->base++;
free(s->base);
}

s->base = s->top = NULL;
s->stacksize  = 0;
}

int main(void)
{
sqstack s;
int i,c,k;
int j = 0;               //用来记录转化后的8进制数位数
int N;
printf("请输入一个十进制数:");
scanf("%d",&N);
int W = N;

IntiStack(&s);           //初始化栈

while(N != 0)          //除k取余法转换,并把余数入栈
{
k = N%8;
Push(&s,k);
N = N/8;
j++;
}

printf("十进制数 %d 转化为八进制数为: ",W);
for( i=0; i<j; i++)
{
Pop(&s,&c);
printf("%d ",c);
}

//DestoryStack(&s);
printf("\n");
return 0;
}


运行结果

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