解决Program received signal SIGSEGV, Segmentation fault.的辛酸
2016-10-21 15:45
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最近写一个算法很简单,涉及到链表的归并,在追求速度的时候,尽最大程度上使用了指针,然而却带来了异常灾难。
编译通过,在debug的时候,我看见了这个。。。。。Program received signal SIGSEGV, Segmentation fault。omg,我准备解决这个问题,耗费了我整整一天来review代码。
其实解决这个问题很简单,只是我们没有抓住一个关键点。
声明指针不会创建用于存储的内存空间。
指针声明时,指向的位置不确定,程序运行时,如果你运气好可能不出错,但是下次动态分配内存的时候你可能就没这么幸运了。
例子
详细的解决办法可以参考:http://www.cnblogs.com/panfeng412/archive/2011/11/06/2237857.html
编译通过,在debug的时候,我看见了这个。。。。。Program received signal SIGSEGV, Segmentation fault。omg,我准备解决这个问题,耗费了我整整一天来review代码。
其实解决这个问题很简单,只是我们没有抓住一个关键点。
声明指针不会创建用于存储的内存空间。
指针声明时,指向的位置不确定,程序运行时,如果你运气好可能不出错,但是下次动态分配内存的时候你可能就没这么幸运了。
例子
int *a; *a=12;
这是一个典型的错误:因为在分配内存时你无法确定 a 指向的位置,所以你下次 *a或者访问a时,可能带来:Program received signal SIGSEGV, Segmentation fault.
详细的解决办法可以参考:http://www.cnblogs.com/panfeng412/archive/2011/11/06/2237857.html
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