NYOJ-64 鸡兔同笼

#include <iostream>
#include <string>
#include <cstring>
#include <cmath>
#include <algorithm>
using namespace std;

int main()
{
int t;
int n,m;

cin>>t;

while(t--)
{
cin>>n>>m;
int x=(m-2*n)/2;
if((m-2*n)%2 || (m-2*n)<=0)
cout<<"No answer"<<endl;
else
cout<<n-x<<" "<<x<<endl;
}

return 0;
}