hdu2266 How Many Equations Can You Find
2016-10-18 17:26
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Description
Now give you an string which only contains 0, 1 ,2 ,3 ,4 ,5 ,6 ,7 ,8 ,9.You are asked to add the sign ‘+’ or ’-’ between the characters. Just like give you a string “12345”, you can work out a string “123+4-5”. Now give you an integer N, please tell me how many ways can you find to make the result of the string equal to N .You can only choose at most one sign between two adjacent characters.
Input
Each case contains a string s and a number N . You may be sure the length of the string will not exceed 12 and the absolute value of N will not exceed 999999999999.
Output
The output contains one line for each data set : the number of ways you can find to make the equation.
Sample Input
123456789 3
21 1
Sample Output
18
1
方法:搜素 递归
Now give you an string which only contains 0, 1 ,2 ,3 ,4 ,5 ,6 ,7 ,8 ,9.You are asked to add the sign ‘+’ or ’-’ between the characters. Just like give you a string “12345”, you can work out a string “123+4-5”. Now give you an integer N, please tell me how many ways can you find to make the result of the string equal to N .You can only choose at most one sign between two adjacent characters.
Input
Each case contains a string s and a number N . You may be sure the length of the string will not exceed 12 and the absolute value of N will not exceed 999999999999.
Output
The output contains one line for each data set : the number of ways you can find to make the equation.
Sample Input
123456789 3
21 1
Sample Output
18
1
方法:搜素 递归
#include<stdio.h> #include<string.h> using namespace std; __int64 n,sum; char a[13]; int len; void dfs(__int64 x,__int64 num) { if(x==len) { if(num==n) sum++; return ; } __int64 k=0; for(int i=x;i<len;i++) { k=k*10+(a[i]-'0'); dfs(i+1,num+k); if(x) dfs(i+1,num-k); } } int main() { while(~scanf("%s%I64d",a,&n)) { len=strlen(a); sum=0; dfs(0,0); printf("%I64d\n",sum); } return 0; }
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