Service组件 Android 5.0中出现的警告:Service Intent must be explicit
2016-10-10 16:17
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在学习Service组件时,按照书上的例子的,写好,运行点击后,应用闪退,后台报错
![](https://oscdn.geek-share.com/Uploads/Images/Content/201911/10/b505ee9218f49acec7f59be0b000c8c4)
去网上找了下,发现是因为android 5.0存在的问题,正好我编译程序的sdk是5.0.1的。
Android 5.0一出来后,其中有个特性就是Service
Intent must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。
而android源码是这样写的(源码位置:sdk/sources/android-21/android/app/ContextImpl.java):
private void validateServiceIntent(Intent service) {
if (service.getComponent() == null && service.getPackage() == null) {
if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
IllegalArgumentException ex = new IllegalArgumentException(
"Service Intent must be explicit: " + service);
throw ex;
} else {
Log.w(TAG, "Implicit intents with startService are not safe: " + service
+ " " + Debug.getCallers(2, 3));
}
}
}
既然,源码里是这样写的,那么这里有两种解决方法:
1、设置Action和packageName:
参考代码如下:
Intent intent = new Intent();
mIntent.setAction("XXX.XXX.XXX");//你定义的service的action
mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名
context.startService(intent);
此方式是google官方推荐使用的解决方法。
在此附上地址供大家参考:http://developer.android.com/goo
... tml#billing-service,有兴趣的可以去看看。
注意:这里的packageName是当前应用的包名,即AndroidManifest.xml中那个package值,不能是你service所在那个包路径
2、将隐式启动转换为显示启动:--参考地址:http://stackoverflow.com/a/26318757/1446466
public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
// Retrieve all services that can match the given intent
PackageManager pm = context.getPackageManager();
List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);
// Make sure only one match was found
if (resolveInfo == null || resolveInfo.size() != 1) {
return null;
}
// Get component info and create ComponentName
ResolveInfo serviceInfo = resolveInfo.get(0);
String packageName = serviceInfo.serviceInfo.packageName;
String className = serviceInfo.serviceInfo.name;
ComponentName component = new ComponentName(packageName, className);
// Create a new intent. Use the old one for extras and such reuse
Intent explicitIntent = new Intent(implicitIntent);
// Set the component to be explicit
explicitIntent.setComponent(component);
return explicitIntent;
}
复制代码
调用方式如下:
Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");
Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
context.startService(eintent);
复制代码
详细地址:http://blog.csdn.net/vrix/article/details/45289207
去网上找了下,发现是因为android 5.0存在的问题,正好我编译程序的sdk是5.0.1的。
Android 5.0一出来后,其中有个特性就是Service
Intent must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。
而android源码是这样写的(源码位置:sdk/sources/android-21/android/app/ContextImpl.java):
private void validateServiceIntent(Intent service) {
if (service.getComponent() == null && service.getPackage() == null) {
if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
IllegalArgumentException ex = new IllegalArgumentException(
"Service Intent must be explicit: " + service);
throw ex;
} else {
Log.w(TAG, "Implicit intents with startService are not safe: " + service
+ " " + Debug.getCallers(2, 3));
}
}
}
既然,源码里是这样写的,那么这里有两种解决方法:
1、设置Action和packageName:
参考代码如下:
Intent intent = new Intent();
mIntent.setAction("XXX.XXX.XXX");//你定义的service的action
mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名
context.startService(intent);
此方式是google官方推荐使用的解决方法。
在此附上地址供大家参考:http://developer.android.com/goo
... tml#billing-service,有兴趣的可以去看看。
注意:这里的packageName是当前应用的包名,即AndroidManifest.xml中那个package值,不能是你service所在那个包路径
2、将隐式启动转换为显示启动:--参考地址:http://stackoverflow.com/a/26318757/1446466
public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
// Retrieve all services that can match the given intent
PackageManager pm = context.getPackageManager();
List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);
// Make sure only one match was found
if (resolveInfo == null || resolveInfo.size() != 1) {
return null;
}
// Get component info and create ComponentName
ResolveInfo serviceInfo = resolveInfo.get(0);
String packageName = serviceInfo.serviceInfo.packageName;
String className = serviceInfo.serviceInfo.name;
ComponentName component = new ComponentName(packageName, className);
// Create a new intent. Use the old one for extras and such reuse
Intent explicitIntent = new Intent(implicitIntent);
// Set the component to be explicit
explicitIntent.setComponent(component);
return explicitIntent;
}
复制代码
调用方式如下:
Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");
Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
context.startService(eintent);
复制代码
详细地址:http://blog.csdn.net/vrix/article/details/45289207
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