LeetCode[162] Find Peak Element
2016-10-09 22:51
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A peak element is an element that is greater than its neighbors.
Given an input array where
The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.
You may imagine that
For example, in array
the index number 2.
class Solution {
public:
int findPeakElement(vector<int>& nums) {
int n = nums.size();
if (nums[0] > nums[1]) return 0;
if (nums[n - 1] > nums[n - 2]) return n - 1;
for (int i = 1; i < n - 1; ++i) {
if (nums[i] > nums[i - 1] && nums[i] > nums[i + 1])
return i;
}
return 0;
}
};
Given an input array where
num[i] ≠ num[i+1], find a peak element and return its index.
The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.
You may imagine that
num[-1] = num = -∞.
For example, in array
[1, 2, 3, 1], 3 is a peak element and your function should return
the index number 2.
class Solution {
public:
int findPeakElement(vector<int>& nums) {
int n = nums.size();
if (nums[0] > nums[1]) return 0;
if (nums[n - 1] > nums[n - 2]) return n - 1;
for (int i = 1; i < n - 1; ++i) {
if (nums[i] > nums[i - 1] && nums[i] > nums[i + 1])
return i;
}
return 0;
}
};
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