【leetcode】3.Longest Substring Without Repeating Characters
2016-09-30 23:14
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Question
Given a string, find the length of the longest substring without repeating characters.
Example
Given "abcabcbb" , the answer is"abc", which the length is 3.
Given "bbbb", the answer is
Given "pwwkew", the answer is"wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
Solution
Given a string, find the length of the longest substring without repeating characters.
Example
Given "abcabcbb" , the answer is"abc", which the length is 3.
Given "bbbb", the answer is
"b", with the length of 1.
Given "pwwkew", the answer is"wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
Solution
public class Solution { public int lengthOfLongestSubstring(String s) { if(s.length()<=1){ //如果字符串长度为0或1,返回其长度 return s.length(); } String temp=s.substring(0,1); //截取字符串s的第一个字符 int max=1; for(int i=1;i<s.length();i++){ //判断子串中是否有跟当前s.charAt(i)一样的字符 if(!temp.contains(String.valueOf(s.charAt(i)))){ temp+=s.charAt(i); } else{ if(max<temp.length()){ max=temp.length(); } //若有,则从下一个字符开始截取后半段字符串 temp=temp.substring(temp.indexOf(s.charAt(i))+1)+String.valueOf(s.charAt(i)); } if(max<temp.length()){ max=temp.length(); } } return max; } }
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