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[hdu 3966 Aragorn's Story] 点权树链剖分

2016-09-28 00:28 411 查看

[hdu 3966 Aragorn’s Story] 点权树链剖分

题目链接[hdu 3966 Aragorn’s Story]

题意描述: 给定一个N个点的树,以及树上的点对应的初始权值。接下来有P次操作,操作一:将顶点u到顶点v的路径上的所有点权±x,操作二:求顶点u上的权值。

解题思路:点权的树链剖分以及区间更新和单点求值。

/****************************>>>>HEADFILES<<<<****************************/
#include <set>
#include <map>
#include <list>
#include <cmath>
#include <queue>
#include <vector>
#include <cstdio>
#include <string>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <sstream>
#include <algorithm>
using namespace std;
/****************************>>>>>DEFINE<<<<<*****************************/
#define fst             first
#define snd             second
#define root            1, N, 1
#define lson            l, mid, (rt << 1)
#define rson            mid + 1, r, (rt << 1 | 1)
#define __mid__         int mid = (l + r) >> 1
#define PB(a)           push_back(a)
#define MP(a,b)         make_pair(a,b)
#define FIN             freopen("input.txt","r",stdin)
#define FOUT            freopen("output.txt","w",stdout)
//#pragma comment(linker, "/STACK:1024000000,1024000000")
typedef __int64         LL;
const int INF = 0x3f3f3f3f;
const int MAXN = 50000 + 5;
/****************************>>>>SEPARATOR<<<<****************************/

int N, M, P, A[MAXN];

struct Edge {
int v, next;
Edge() {}
Edge(int v, int next) : v(v), next(next) {}
} edge[MAXN << 1];
int head[MAXN], ESZ;
int siz[MAXN], top[MAXN], fa[MAXN], son[MAXN], dep[MAXN], tid[MAXN], rk[MAXN], id;
int seg[MAXN << 2], tag[MAXN << 2];

void init() {
ESZ = 0;
id = 0;
memset(head, -1, sizeof(head));
memset(son, -1, sizeof(son));
}
void add_edge(int u, int v) {
edge[ESZ] = Edge(v, head[u]);
head[u] = ESZ ++;
}
void dfs1(int u, int pre, int k) {
int v;
siz[u] = 1;
fa[u] = pre;
dep[u] = k;
for(int i = head[u]; ~i; i = edge[i].next) {
v = edge[i].v;
if(v == pre) continue;
dfs1(v, u, k + 1);
siz[u] += siz[v];
if(son[u] == -1 || siz[son[u]] < siz[v]) son[u] = v;
}
}
void dfs2(int u, int tp) {
int v;
tid[u] = ++ id;
rk[tid[u]] = u;
top[u] = tp;
if(son[u] == -1) return;
dfs2(son[u], tp);
for(int i = head[u]; ~i; i = edge[i].next) {
v = edge[i].v;
if(v == fa[u] || v == son[u]) continue;
dfs2(v, v);
}
}
inline void pushUp(const int& rt) {
seg[rt] = seg[rt << 1] + seg[rt << 1 | 1];
}
inline void pushDown(int w, const int& rt)  {
if(tag[rt]) {
seg[rt << 1] += (w - (w >> 1)) * tag[rt];
seg[rt << 1 | 1] += (w >> 1) * tag[rt];
tag[rt << 1] += tag[rt];
tag[rt << 1 | 1] += tag[rt];
tag[rt] = 0;
}
}
void build(int l, int r, int rt) {
tag[rt] = 0;
if(l == r) {
seg[rt] = A[rk[l]];
return;
}
__mid__;
build(lson);
build(rson);
pushUp(rt);
}
int query(const int& p, int l, int r, int rt) {
if(l == r) {
tag[rt] = 0;
return seg[rt];
}
__mid__;
pushDown(r - l + 1, rt);
return p <= mid ? query(p, lson) : query(p, rson);
}
void update(const int& L, const int& R, const int& x, int l, int r, int rt) {
if(L <= l && r <= R) {
seg[rt] += (r - l + 1) * x;
tag[rt] += x;
return;
}
__mid__;
pushDown(r - l + 1, rt);
if(L <= mid) update(L, R, x, lson);
if(R > mid) update(L, R, x, rson);
pushUp(rt);
}
void modify(int u, int v, int x) {
int f1 = top[u], f2 = top[v];
while(f1 != f2) {
if(dep[f1] < dep[f2]) {
swap(u, v);
swap(f1, f2);
}
update(tid[f1], tid[u], x, 1, id, 1);
u = fa[f1], f1 = top[u];
}
if(dep[u] > dep[v]) swap(u, v);
update(tid[u], tid[v], x, 1, id, 1);
}

char op[5];
int main() {
#ifndef ONLINE_JUDGE
FIN;
#endif // ONLINE_JUDGE
int u, v, x;
while(~scanf("%d %d %d", &N, &M, &P)) {
init();
for(int i = 1; i <= N; i ++) {
scanf("%d", &A[i]);
}
for(int i = 1; i <= M; i ++) {
scanf("%d %d", &u, &v);
add_edge(u, v);
add_edge(v, u);
}
dfs1(1, -1, 1);
dfs2(1, 1);
build(1, id, 1);
while(P --) {
scanf("%s", op);
if(op[0] == 'Q') {
scanf("%d", &u);
printf("%d\n", query(tid[u], 1, id, 1));
} else {
scanf("%d %d %d", &u, &v, &x);
if(op[0] == 'D') x = -x;
modify(u, v, x);
}
}
}
return 0;
}
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