BZOJ 2002 [Hnoi2010]Bounce 弹飞绵羊
2016-09-25 14:26
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分块
分为根号n块,对每一个装置,记录它跳出所在块需要的步数和跳出所在块之后到达的点。复杂度就是O(根号n)了
分为根号n块,对每一个装置,记录它跳出所在块需要的步数和跳出所在块之后到达的点。复杂度就是O(根号n)了
#include<cstdio> #include<cmath> #define N 200005 #define SN 1000 using namespace std; int k , step , next , n, block, cnt, l[SN], r[SN], belong ; void init() { block=sqrt(n); if(block*block==n)cnt=block; else cnt=block+1; l[1]=0; r[1]=block-1; for(int i = 2; i <= block; i++) { l[i]=l[i-1]+block; r[i]=r[i-1]+block; } if(cnt>block) l[cnt]=l[cnt-1]+block, r[cnt]=n-1; for(int i = 1; i <= cnt; i++) { for(int j = r[i]; j >= l[i]; j--) { belong[j]=i; if(j+k[j]>r[i])step[j]=1, next[j]=j+k[j]; else step[j]=step[j+k[j]]+1, next[j]=next[j+k[j]]; } } } int main() { scanf("%d",&n); for(int i = 0; i < n; i++) scanf("%d",&k[i]); init(); int m; scanf("%d",&m); while(m--) { int cmd, x, y; scanf("%d",&cmd); if(cmd==1) { scanf("%d",&x); int ans=0; while(x<n) { ans+=step[x]; x=next[x]; } printf("%d\n",ans); } else { scanf("%d%d",&x,&y); k[x]=y; for(int i = x, ii = l[belong[x]]; i >= ii; i--) { if(i+k[i]>r[belong[x]])step[i]=1,next[i]=i+k[i]; else step[i]=step[i+k[i]]+1, next[i]=next[i+k[i]]; } } } }
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