程序员面试宝典：输出zigzag数组

一道题，感觉有点意思，稍微做了做

int func(int m, int n)
{
if(m==0&&n==0)
return 0;
else if((m==0&&n!=0))
{
return n%2==0? func(m+1,n-1)+1: func(m,n-1)+1;
}
else if((m!=0&&n==0))
{
return m%2==0? func(m-1,n)+1: func(m-1,n+1)+1;
}
else if((m==7&&n!=7))
{
return n%2==0? func(m-1,n+1)+1: func(m,n-1)+1;
}
else if((m!=7&&n==7))
{
return m%2==0? func(m-1,n)+1: func(m+1,n-1)+1;
}
else if((m==7&&n==7))
{
return 63;
}
else
{
return (m+n)%2==0? func(m+1,n-1)+1: func(m-1,n+1)+1;
}
}
int main(void)
{
int b[8][8];
for(int i=0;i<8;i++)
{
for(int j=0;j<8;j++)
{
b[i][j]=func(i,j);
cout<<b[i][j]<<", ";
}
cout<<endl;
}
}