Java之——数字金额转化为英文金额

转载请注明出处：http://blog.csdn.net/l1028386804/article/details/52599090

今天，给大家带来一篇基于Java将数字金额转化为英文金额的示例代码，网上有很多类似的代码，但是，它们不是转化错误就是不支持小数，那现在我们就一起实现一个完美的数字金额转化为英文金额的示例代码吧，不多说了，详情参见如下代码：

package com.lyz.util;

/**
* 将数字转化为英文金额
* @author liuyazhuang
*
*/
public class NumberParser {

public static void main(String[] args) {
System.out.println(NumberParser.parse("0.0"));
}
//10以内的数字
private static final String[] SINGLE_NUM_ARR = new String[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
//十几的数字
private static final String[] TEN_NUM_ARR = new String[] { "Ten", "Eleven", "Tweleve", "Thirteen", "Fourteen", "Fifteen", "Sixteen","Seventeen", "Eighteen", "Nineteen" };
//整十的数字
private static final String[] TEN_INTEGER_ARR = new String[] { "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };

public static String parse(String x) {
if(Double.parseDouble(x) <= 0){
return "Zero Cents only";
}
int z = x.indexOf("."); // 取小数点位置
String lstr = "", rstr = "";
if (z > -1) { // 看是否有小数，如果有，则分别取左边和右边
lstr = x.substring(0, z);
rstr = x.substring(z + 1);
} else // 否则就是全部
lstr = x;

String lstrrev = reverse(lstr); // 对左边的字串取反
String[] a = new String[5]; // 定义5个字串变量来存放解析出来的叁位一组的字串

switch (lstrrev.length() % 3) {
case 1:
lstrrev += "00";
break;
case 2:
lstrrev += "0";
break;
}
String lm = ""; // 用来存放转换後的整数部分
for (int i = 0; i < lstrrev.length() / 3; i++) {
a[i] = reverse(lstrrev.substring(3 * i, 3 * i + 3)); // 截取第一个叁位
if (!a[i].equals("000")) { // 用来避免这种情况：1000000 = one million
if (i != 0)
lm = transThree(a[i]) + " " + parseMore(String.valueOf(i)) + " " + lm; // 加:
// thousand、million、billion
else
lm = transThree(a[i]); // 防止i=0时， 在多加两个空格.
} else
lm += transThree(a[i]);
}

String xs = ""; // 用来存放转换後小数部分
if (z > -1){
String transTwo =  transTwo(rstr);
if(transTwo == null || "".equals(transTwo)){
xs = "";
}else{
xs = "and " + transTwo + " Cents "; // 小数部分存在时转换小数
}
}
return lm.trim() + " " + xs + "only";
}

private static String parseFirst(String s) {
//String[] a = new String[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
return SINGLE_NUM_ARR[Integer.parseInt(s.substring(s.length() - 1))];
}

private static String parseTeen(String s) {
//String[] a = new String[] { "Ten", "Eleven", "Tweleve", "Thirteen", "Fourteen", "Fifteen", "Sixteen","Seventeen", "Eighteen", "Nineteen" };
return TEN_NUM_ARR[Integer.parseInt(s) - 10];
}

private static String parseTen(String s) {
//String[] a = new String[] { "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
return TEN_INTEGER_ARR[Integer.parseInt(s.substring(0, 1)) - 1];
}

// 两位
private static String transTwo(String s) {
String value = "";
// 判断位数
if (s.length() > 2)
s = s.substring(0, 2);
else if (s.length() < 2)
s = s + "0";

if (s.startsWith("0")) // 07 - seven 是否小於10
value = parseFirst(s);
else if (s.startsWith("1")) // 17 seventeen 是否在10和20之间
value = parseTeen(s);
else if (s.endsWith("0")) // 是否在10与100之间的能被10整除的数
value = parseTen(s);
else
value = parseTen(s) + " " + parseFirst(s);
return value;
}

private static String parseMore(String s) {
String[] a = new String[] { "", "Thousand", "Million", "Billion" };
return a[Integer.parseInt(s)];
}

// 制作叁位的数
// s.length = 3
private static String transThree(String s) {
String value = "";
if (s.startsWith("0")) // 是否小於100
value = transTwo(s.substring(1));
else if (s.substring(1).equals("00")) // 是否被100整除
value = parseFirst(s.substring(0, 1)) + " Hundred";
else
value = parseFirst(s.substring(0, 1)) + " Hundred and " + transTwo(s.substring(1));
return value;
}

private static String reverse(String s) {
char[] aChr = s.toCharArray();
StringBuffer tmp = new StringBuffer();
for (int i = aChr.length - 1; i >= 0; i--) {
tmp.append(aChr[i]);
}
return tmp.toString();
}
}