Leetcode 380. Insert Delete GetRandom O(1) 常数增删改系统 解题报告
2016-09-17 16:00
477 查看
1 解题思想
这道题是要设计一个常数时间内增加,删除,随机查询的数据结构,数值不会重复。重点在于如何做到常数内删除?
思想其实也很简单,使用一个HashMap保存每个值的位置就可以了,然后全部值存到一个ArrayList里面,删除的时候讲删除的那个位置的值进行调换,将ArrayList里面最后一位的值提到要删除的那个位置上覆盖,然后直接删除ArrayList的最后一个
对应的下一题,建议看完后再看这个:
Leetcode 381. Insert Delete GetRandom O(1) - Duplicates allowed 可重复常数增删改系统 解题报告
2 原题
Design a data structure that supports all following operations in average O(1) time. insert(val): Inserts an item val to the set if not already present. remove(val): Removes an item val from the set if present. getRandom: Returns a random element from current set of elements. Each element must have the same probability of being returned. Example: // Init an empty set. RandomizedSet randomSet = new RandomizedSet(); // Inserts 1 to the set. Returns true as 1 was inserted successfully. randomSet.insert(1); // Returns false as 2 does not exist in the set. randomSet.remove(2); // Inserts 2 to the set, returns true. Set now contains [1,2]. randomSet.insert(2); // getRandom should return either 1 or 2 randomly. randomSet.getRandom(); // Removes 1 from the set, returns true. Set now contains [2]. randomSet.remove(1); // 2 was already in the set, so return false. randomSet.insert(2); // Since 1 is the only number in the set, getRandom always return 1. randomSet.getRandom();
3 AC解
public class RandomizedSet { //用来索引下在ArrayList中的关系,做到快速定位 private HashMap<Integer,Integer> locations; //存储原始数据 private ArrayList<Integer> list; private Random random; /** Initialize your data structure here. */ public RandomizedSet() { this.locations = new HashMap<Integer,Integer>(); this.list = new ArrayList<Integer>(); this.random = new Random(); } /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */ /** * 判断后直接插入 * */ public boolean insert(int val) { if( locations.containsKey(val) == true ) return false; locations.put(val,list.size()); list.add(val); return true; } /** Removes a value from the set. Returns true if the set contained the specified element. */ /** * 核心思想在于:把删除的元素交换到ArrayList最后一位上,这样就可以O1完成了 * */ public boolean remove(int val) { if( locations.containsKey(val) == false) return false; int tmpLocation = locations.get(val); if(tmpLocation != list.size() - 1){ int lastVal = list.get(list.size() -1 ); list.set(tmpLocation,lastVal); locations.put(lastVal,tmpLocation); } list.remove(list.size() - 1); locations.remove(val); return true; } /** Get a random element from the set. */ public int getRandom() { return list.get(random.nextInt(list.size())); } } /** * Your RandomizedSet object will be instantiated and called as such: * RandomizedSet obj = new RandomizedSet(); * boolean param_1 = obj.insert(val); * boolean param_2 = obj.remove(val); * int param_3 = obj.getRandom(); */
相关文章推荐
- [Leetcode] 380. Insert Delete GetRandom O(1) 解题报告
- [leetcode] 380. Insert Delete GetRandom O(1) 解题报告
- Leetcode 381. Insert Delete GetRandom O(1) - Duplicates allowed 可重复常数增删改系统 解题报告
- LeetCode 380. Insert Delete GetRandom O(1) (插入删除和获得随机数 常数时间)
- Leetcode 355. Design Twitter 实现一个Twitter系统 解题报告
- [leetcode] 380. Insert Delete GetRandom O(1)
- LeetCode 380. Insert Delete GetRandom O(1) 题解
- leetcode380. Insert Delete GetRandom O(1)
- [LeetCode] Insert Delete GetRandom O(1) 常数时间内插入删除和获得随机数
- 【Leetcode】380. Insert Delete GetRandom O(1)
- 【leetcode】380. Insert Delete GetRandom O(1)
- LeetCode 380. Insert Delete GetRandom O(1)
- LeetCode 380. Insert Delete GetRandom O(1)
- LeetCode—380. Insert Delete GetRandom O(1)s
- [leetcode]380. Insert Delete GetRandom O(1)j
- [leetcode] 237. Delete Node in a Linked List 解题报告
- [LeetCode] Insert Delete GetRandom O(1) - Duplicates allowed 常数时间内插入删除和获得随机数 - 允许重复
- [leetcode] 380. Insert Delete GetRandom O(1)
- leetcode 380. Insert Delete GetRandom O(1)
- [Leetcode] 237. Delete Node in a Linked List 解题报告