Codeforces 371C - Sonya and Queries(思维)

C. Sonya and Queries

time limit per test1 second

memory limit per test256 megabytes

inputstandard input

outputstandard output

Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her t queries, each of one of the following type:

 +  ai — add non-negative integer ai to the multiset. Note, that she has a multiset, thus there may be many occurrences of the same integer.

 -  ai — delete a single occurrence of non-negative integer ai from the multiset. It’s guaranteed, that there is at least one ai in the multiset.

? s — count the number of integers in the multiset (with repetitions) that match some pattern s consisting of 0 and 1. In the pattern, 0 stands for the even digits, while 1 stands for the odd. Integer x matches the pattern s, if the parity of the i-th from the right digit in decimal notation matches the i-th from the right digit of the pattern. If the pattern is shorter than this integer, it’s supplemented with 0-s from the left. Similarly, if the integer is shorter than the pattern its decimal notation is supplemented with the 0-s from the left.

For example, if the pattern is s = 010, than integers 92, 2212, 50 and 414 match the pattern, while integers 3, 110, 25 and 1030 do not.

Input

The first line of the input contains an integer t (1 ≤ t ≤ 100 000) — the number of operation Sonya has to perform.

Next t lines provide the descriptions of the queries in order they appear in the input file. The i-th row starts with a character ci — the type of the corresponding operation. If ci is equal to ‘+’ or ‘-’ then it’s followed by a space and an integer ai (0 ≤ ai < 1018) given without leading zeroes (unless it’s 0). If ci equals ‘?’ then it’s followed by a space and a sequence of zeroes and onse, giving the pattern of length no more than 18.

It’s guaranteed that there will be at least one query of type ‘?’.

It’s guaranteed that any time some integer is removed from the multiset, there will be at least one occurrence of this integer in it.

Output

For each query of the third type print the number of integers matching the given pattern. Each integer is counted as many times, as it appears in the multiset at this moment of time.

Examples

input

12

+ 1

+ 241

? 1

+ 361

- 241

? 0101

+ 101

? 101

- 101

? 101

+ 4000

? 0

output

2

1

2

1

1

input

4

+ 200

+ 200

- 200

? 0

output

1

Note

Consider the integers matching the patterns from the queries of the third type. Queries are numbered in the order they appear in the input.

1 and 241.

361.

101 and 361.

361.

4000.

题意:

给出三种输入形式:

1.’+’添加一个数到数组

2.’-‘去掉数组中的某个数

3.’?’给出01字符串,表示查询的数的特征(对应数位的奇偶情况,比喻250对应010,233对应011),查询符合字符串特征的数的数量,如果长度不够,就在字符串前面补0.

解题思路:

把每个数按照特征转换成01,然后再把01串看做成二进制数,转化成十进制数,然后实际存的是一类特征数的个数.搜索的时候也是把01串转化成十进制数,然后检索.

AC代码:

#include<stdio.h>
const int maxn = 1000005;
int qdu[maxn];
int main()
{
int loop;
scanf("%d",&loop);
while(loop--)
{
char tmp1;
long long tmp2;
scanf(" %c %lld",&tmp1,&tmp2);
int sum = 0;
int k = 1;
while(tmp2)
{
sum += k*(tmp2%2);
tmp2 /= 10;
k <<= 1;
}
if(tmp1 == '+') qdu[sum]++;
else if(tmp1 == '-') qdu[sum]--;
else if(tmp1 == '?') printf("%d\n",qdu[sum]);
}
return 0;
}