MyEclipse下的Servlet环境搭建指南

打开MyEclipse，在Package中右击新建一个web工程



新建web工程后



MyEclipse会自动生成Servlet文件并且在web.xml中注册Servlet

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <display-name></display-name>
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>LoginServlet</servlet-name>
<servlet-class>cn.pzh.servlet.LoginServlet</servlet-class>
</servlet>
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>RegisterServlet</servlet-name>
<servlet-class>cn.pzh.servlet.RegisterServlet</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>LoginServlet</servlet-name>
<url-pattern>/servlet/LoginServlet</url-pattern>
</servlet-mapping<
bcfb
/span>>
<servlet-mapping>
<servlet-name>RegisterServlet</servlet-name>
<url-pattern>/servlet/RegisterServlet</url-pattern>
</servlet-mapping>

<welcome-file-list>
<welcome-file>login.jsp</welcome-file>
</welcome-file-list>
</web-app>

Servlet中跳转页面的方法

RequestDispatcher rd = request.getRequestDispatcher("index.jsp");

form表单的提交代码

<form action="/FindPasswordDemo/servlet/LoginServlet" method="post">
用户名：<input type="text" id="userName" name="userName" /><br/>
密 码：<input type="password" id="password" name="password" /><br/>
   <input type="submit" value="提交"/>      
<input type="button" value="注册" onClick="window.location.href='register.jsp'"/><br>
</form>