URAL 1208 Legendary Teams Contest（DFS）

Legendary Teams Contest

Time limit: 1.0 second
Memory limit: 64 MB

Nothing
makes as old as years. A lot of cool contests are gone, a lot of
programmers are not students anymore and are not allowed to take part at
the contests. Though their spirit is fresh and young as it was years
ago! And so once they decided to make a contest at the Ural State
University among the veteran teams…

To
make the contest interesting, they decided to invite as much
"legendary" teams as possible. The jury has made a short list of teams,
which have shown the best results in the old good times, thus being
worthy to hold the name of "legendary". All those teams were invited to
take part of the contest, and all of them accepted the invitations. But
they have forgotten one important thing at the jury: during the long
history of the contests at the university, the teams happened to change
and some programmers managed to contest in different "legendary" teams.
Though, the jury decided not to give up the initial idea and to form as
much legendary teams as possible to participate at the contest — and
your program should help the jury!

Input

The first line contains a positive integer K, 1 ≤ K ≤ 18. It is the number of all the legendary teams. There follow the descriptions of the teams in K
lines. Each of those lines contains three names of the team members of
the respective team. All names are written with not more than 20 small
Latin letters.

Output

You
should output the maximal possible number of legendary teams of
veterans, that could simultaneously participate at the contest.

Sample

input	output
7 gerostratos scorpio shamgshamg zaitsev silverberg cousteau zaitsev petersen shamgshamg clipper petersen shamgshamg clipper bakirelli vasiliadi silverberg atn dolly knuth dijkstra bellman	4

Problem Author: Leonid Volkov
【分析】简单dfs.

#include <iostream>
#include <cstring>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <time.h>
#include <string>
#include <map>
#include <stack>
#include <vector>
#include <set>
#include <queue>
#define inf 0x3f3f3f3f
#define mod 10000
typedef long long ll;
using namespace std;
const int N=505;
const int M=100005;
map<string,int>f;
struct node {
int a,b,c;
} p[20];
int n,maxz;
int vis[60];

void dfs(int v,int u) {
maxz = max(maxz,v);
if(u>n)
return ;
if(!vis[p[u].a]&&!vis[p[u].b]&&!vis[p[u].c]) {
vis[p[u].a] = vis[p[u].b] = vis[p[u].c] = 1;
dfs(v+1,u+1);
vis[p[u].a] = vis[p[u].b] = vis[p[u].c] = 0;
}
dfs(v,u+1);
}
int main() {
int i,g=0;
char s1[22],s2[22],s3[22];
scanf("%d",&n);
for(i = 1 ; i <= n ; i++) {
scanf("%s%s%s",s1,s2,s3);
if(!f[s1])f[s1] = ++g;
if(!f[s2])f[s2] = ++g;
if(!f[s3])f[s3] = ++g;
p[i].a = f[s1];
p[i].b = f[s2];
p[i].c = f[s3];
}
for(i = 1 ; i <= n ; i++) {
vis[p[i].a] = vis[p[i].b] = vis[p[i].c] = 1;
dfs(1,i+1);
vis[p[i].a] = vis[p[i].b] = vis[p[i].c] = 0;
}
printf("%d\n",maxz);
return 0;
}

View Code