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swift 互斥锁lock学习

2016-09-13 14:17 127 查看

一些学习过程中的难点解决

lock锁看了一片文章,写的很牛车:http://blog.csdn.net/hello_hwc/article/details/50037505

例子

lock锁,我是用于两个线程同时执行一段代码或者一个方法,比如同时刷新auth认证,例如:

class ViewController: UIViewController {
let lock = NSLock()
var person = Person(name: "Leo", age: 23)
override func viewDidLoad() {
super.viewDidLoad()
let queue1 = dispatch_queue_create("com.test.queue1", DISPATCH_QUEUE_SERIAL)
let queue2 = dispatch_queue_create("com.test.queue1", DISPATCH_QUEUE_SERIAL)
dispatch_async(queue1) { () -> Void in
self.lock.lock()
self.person.update("queue1", delay: 2, age: 1)
self.lock.unlock()
}
dispatch_async(queue2) { () -> Void in
self.lock.lock()
self.person.update("queue2", delay: 1, age: 2)
self.lock.unlock()
}
self.performSelector("logPerson", withObject: nil, afterDelay: 4)
// Do any additional setup after loading the view, typically from a nib.
}
func logPerson(){
NSLog("%@ %d", person.name,person.age)
}

}


这样就会当执行 self.person.update(“queue2”, delay: 1, age: 2)时候锁定,执行完后释放锁,然后下一个线程才会重新调用update,这样数据不会错乱

我的代码是这样的:

case .Failure(let error):
if response.response?.statusCode == 401{//刷新token
dispatch_async(queue3) { () -> Void in
lock?.lock()//这里添加互斥锁,防止一起刷新token,这样就会分开之行token方法cjq
RefreshToken({ (AnyObject) in
lock?.unlock()
var hs = headers
hs!["Authorization"] = NSUserDefaults.standardUserDefaults().stringForKey("access_token")
}
}, logOut: { (NSError) in
logOut?()
lock?.unlock()
})
}
}else{
failure?(error)
}
}


RefreshToken(success:((AnyObject?) -> Void)?, logOut:((NSError?) -> Void))是闭包函数
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标签:  swift 线程 lock 互斥锁