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SpringMVC接收页面表单参数

2016-09-11 16:58 555 查看
在公司使用的是springmvc，so要好好的学习，以前一直用的是Struts，接触到新领域，特别来了兴趣，还是老习惯，没事写各种demo，今天就来一个简单的页面表单参数



页面简单的代码如下

<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add User</title>

<script type="text/javascript">
//添加用户
function addUser() {
var form = document.forms[0];
form.action = "${pageContext.request.contextPath}/user/addUser1";
//form.action = "${pageContext.request.contextPath}/user/addUser2";
//form.action = "${pageContext.request.contextPath}/user/addUser3";
form.method = "post";
form.submit();
}
</script>

</head>
<body>
<form>
<table>
<tr>
<td>账号</td>
<td>
<input type="text" name="userName">
</td>
</tr>
<tr>
<td>密码</td>
<td>
<input type="password" name="password">
</td>
</tr>
<tr>
<td> </td>
<td>
<input type="button" value="提交" onclick="addUser()">
</td>
</tr>
</table>
</form>
</body>
</html>


1、直接把表单的参数写在Controller相应的方法的形参中

@RequestMapping("/addUser1")
public String addUser1(String userName,String password) {
System.out.println("userName is:"+userName);
System.out.println("password is:"+password);
return "/user/success";
}


2、通过HttpServletRequest接收

@RequestMapping("/addUser2")
public String addUser2(HttpServletRequest request) {
String userName = request.getParameter("userName");
String password = request.getParameter("password");
System.out.println("userName is:"+userName);
System.out.println("password is:"+password);
return "/user/success";
}


3、通过一个bean来接收

　　　　1）建立一个和表单中参数对应的bean

　　　　

public class User {

private String userName;

private String password;

public String getUserName() {
return userName;
}

public void setUserName(String userName) {
this.userName = userName;
}

public String getPassword() {
return password;
}

public void setPassword(String password) {
this.password = password;
}
}


public class User {

private String userName;

private String password;

public String getUserName() {
return userName;
}

public void setUserName(String userName) {
this.userName = userName;
}

public String getPassword() {
return password;
}

public void setPassword(String password) {
this.password = password;
}
}


2）用这个bean来封装接收的参数

@RequestMapping("/addUser3")
public String addUser3(User user) {
System.out.println("userName is:"+user.getUserName());
System.out.println("password is:"+user.getPassword());
return "/user/success";
}


4、通过json数据接收

<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add User</title>

<script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#button_submit").click(function(){
var name = $("#userName").val();
var pass = $("#password").val();

var user = {userName:name,password:pass};//拼装成json格式

$.ajax({
type:"POST",
url:"${pageContext.request.contextPath}/user/addUser4",
data:user,
success:function(data){
alert("成功");
},
error:function(e) {
alert("出错："+e);
}
});
});
});
</script>

</head>
<body>
<form>
<table>
<tr>
<td>账号</td>
<td>
<input type="text" id="userName" name="userName">
</td>
</tr>
<tr>
<td>密码</td>
<td>
<input type="password" id="password" name="password">
</td>
</tr>
<tr>
<td> </td>
<td>
<input type="button" id="button_submit" value="提交">
</td>
</tr>
</table>
</form>
</body>
</html>


依然可以使用bean来接收json数据

@RequestMapping("/addUser4")
public String addUser4(User user) {
System.out.println("userName is:"+user.getUserName());
System.out.println("password is:"+user.getPassword());
return "/user/success";
}


5、使用jQuery的serializeArray() 方法序列化表单元素

　　　　如果表单元素很多，手工拼装成json数据非常麻烦，可以使用jQuery提供的serializeArray()方法序列化表单元素，返回json数据结构数据。

　　　　

<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add User</title>

<script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#button_submit").click(function(){

//序列化表单元素，返回json数据
var params = $("#userForm").serializeArray();

//也可以把表单之外的元素按照name value的格式存进来
//params.push({name:"hello",value:"man"});

$.ajax({
type:"POST",
url:"${pageContext.request.contextPath}/user/addUser5",
data:params,
success:function(data){
alert("成功");
},
error:function(e) {
alert("出错："+e);
}
});
});
});
</script>

</head>
<body>
<form id="userForm">
<table>
<tr>
<td>账号</td>
<td>
<input type="text" id="userName" name="userName">
</td>
</tr>
<tr>
<td>密码</td>
<td>
<input type="password" id="password" name="password">
</td>
</tr>
<tr>
<td> </td>
<td>
<input type="button" id="button_submit" value="提交">
</td>
</tr>
</table>
</form>
</body>
</html>


依然可以使用bean来接收json数据：

@RequestMapping("/addUser5")
public String addUser5(User user) {
System.out.println("userName is:"+user.getUserName());
System.out.println("password is:"+user.getPassword());
return "/user/success";
}
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标签：  spring mvc
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