LeetCode 58. Length of Last Word
2016-09-10 23:26
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描述
给出字符串最后一个单词的长度解决
从后向前扫描,扫描时遇到第一个字符开始计算。class Solution { public: int lengthOfLastWord(string s) { int pos = s.size() - 1; int cnt = 0; while (pos >= 0 && s[pos] == ' ') --pos; while (pos >= 0 && s[pos] != ' '){ ++cnt; --pos; } return cnt; } };
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