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[hard]146. LRU Cache

2016-09-08 10:04 267 查看
146. LRU Cache

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: 
get
 and 
set
.

get(key)
 - Get the value (will always be positive) of the key if the key exists in the cache,
otherwise return -1.
set(key, value)
 - Set or insert the value if the key is not already present. When the cache
reached its capacity, it should invalidate the least recently used item before inserting a new item.

很简单,使用hash或者map维护数据和时间的关系

class LRUCache{
map <int, int> data;
map <int, int > timer;
map <int, int> data_time;

int cap, time;
public:
LRUCache(int capacity) {
cap = capacity;
time = 0;
}

void timer_check() {
while (0 == data_time.count(timer.begin() -> second) ||
data_time[timer.begin() -> second] != timer.begin() -> first)
timer.erase(timer.begin());
}

void check() {
timer_check();
while (data.size() > cap) {
data.erase(timer.begin() -> second);
data_time.erase(timer.begin() -> second);
timer.erase(timer.begin());
timer_check();
}
}

int get(int key) {
if (data.count(key)) {
++ time;
timer[time] = key;
data_time[key] = time;
timer_check();
return data[key];
}
return -1;
}
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