Leetcode 26 Remove Duplicates from Sorted Array
2016-09-03 12:36
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Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array nums =
Your function should return length =
It doesn't matter what you leave beyond the new length.
给有序数组去除重复的元素。
实在没什么好说的。
class Solution {
public:
int removeDuplicates(vector<int>& nums) {
int result=0;
if(nums.size()>0) result=1;
for(int i=1;i<nums.size();i++)
{
if(nums[i]!=nums[i-1])
result++;
else
{
nums.erase(nums.begin()+i);
i--;
}
}
return result;
}
};
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array nums =
[1,1,2],
Your function should return length =
2, with the first two elements of nums being
1and
2respectively.
It doesn't matter what you leave beyond the new length.
给有序数组去除重复的元素。
实在没什么好说的。
class Solution {
public:
int removeDuplicates(vector<int>& nums) {
int result=0;
if(nums.size()>0) result=1;
for(int i=1;i<nums.size();i++)
{
if(nums[i]!=nums[i-1])
result++;
else
{
nums.erase(nums.begin()+i);
i--;
}
}
return result;
}
};
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