[leetcode] 386. Lexicographical Numbers
2016-08-27 12:38
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Given an integer n, return 1 - n in lexicographical order.
For example, given 13, return: [1,10,11,12,13,2,3,4,5,6,7,8,9].
Please optimize your algorithm to use less time and space. The input size may be as large as 5,000,000.
解法一:
大神方法,O(n) time O(1) space。
class Solution
4000
{
public:
vector<int> lexicalOrder(int n) {
if (n < 1) return vector<int>();
vector<int> result(n);
result[0] = 1;
for (int i = 1; i < n; ++ i)
result[i] = next(result[i - 1], n);
return result;
}
int next(int last, int n)
{
if (last * 10 <= n)
return last * 10;
if (last == n)
last /= 10;
++last;
while(last % 10 == 0)
last /= 10;
return last;
}
};
For example, given 13, return: [1,10,11,12,13,2,3,4,5,6,7,8,9].
Please optimize your algorithm to use less time and space. The input size may be as large as 5,000,000.
解法一:
大神方法,O(n) time O(1) space。
class Solution
4000
{
public:
vector<int> lexicalOrder(int n) {
if (n < 1) return vector<int>();
vector<int> result(n);
result[0] = 1;
for (int i = 1; i < n; ++ i)
result[i] = next(result[i - 1], n);
return result;
}
int next(int last, int n)
{
if (last * 10 <= n)
return last * 10;
if (last == n)
last /= 10;
++last;
while(last % 10 == 0)
last /= 10;
return last;
}
};
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