uva 11324 The Largest Clique （Tarjan+记忆化）

/*每个环 要么不选 要么全选 可缩点 就得到一个GAD图 然后搞搞算出最大路径*/
#include<iostream>
#include<cstdio>
#include<cstring>
#define maxn 100010
using namespace std;
int T,n,m,num,head[maxn],low[maxn],dfn[maxn],s[maxn],top,vi[maxn];
int sum,belong[maxn],Head[maxn],Num,ans,f[maxn],topt,dp[maxn];
struct node{int v,pre;}e[maxn];
struct Node{int v,pre;}E[maxn];
void add(int from,int to)
{
e[num].v=to;
e[num].pre=head[from];
head[from]=num++;
}
void Add(int from,int to)
{
E[Num].v=to;
E[Num].pre=Head[from];
Head[from]=Num++;
}
void Tarjan(int x)
{
low[x]=dfn[x]=++topt;
s[++top]=x;f[x]=1;
for(int i=head[x];i!=-1;i=e[i].pre)
{
int v=e[i].v;
if(dfn[v]==0)
{
Tarjan(v);low[x]=min(low[x],low[v]);
}
else if(f[v])low[x]=min(low[x],dfn[v]);
}
if(low[x]==dfn[x])
{
sum++;
while(x!=s[top])
{
f[s[top]]=0;belong[s[top]]=sum;top--;vi[sum]++;
}
f[s[top]]=0;belong[s[top]]=sum;top--;vi[sum]++;
}
}
int Dfs(int x)
{
if(dp[x])return dp[x];
int r=0;
for(int i=Head[x];i!=-1;i=E[i].pre)
{
int v=E[i].v;
r=max(r,Dfs(v));
}
return dp[x]=r+vi[x];
}
int main()
{
scanf("%d",&T);
while(T--)
{
memset(belong,0,sizeof(belong));
memset(head,-1,sizeof(head));
memset(Head,-1,sizeof(Head));
memset(low,0,sizeof(low));
memset(dfn,0,sizeof(dfn));
memset(dp,0,sizeof(dp));
memset(vi,0,sizeof(vi));
memset(f,0,sizeof(f));
memset(s,0,sizeof(s));
num=Num=topt=sum=ans=0;
int u,v;
scanf("%d%d",&n,&m);
for(int i=1;i<=m;i++)
{
scanf("%d%d",&u,&v);
add(u,v);
}
for(int i=1;i<=n;i++)
if(dfn[i]==0)
Tarjan(i);
for(int u=1;u<=n;u++)
for(int i=head[u];i!=-1;i=e[i].pre)
{
int U=belong[u],V=belong[e[i].v];
if(U!=V)Add(U,V);
}
for(int i=1;i<=sum;i++)
ans=max(ans,Dfs(i));
printf("%d\n",ans);
}
}