【Light-oj】-1043 - Triangle Partitioning（数学）

1043 - Triangle Partitioning

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Time Limit: 0.5 second(s)

Memory Limit: 32 MB

See the picture below.



You are given AB, AC and BC. DE is parallel to BC. You are also given the area ratio between ADE and BDEC. You have to find the value of AD.

Input

Input starts with an integer T (≤ 25), denoting the number of test cases.

Each case begins with four real numbers denoting AB, AC, BC and the ratio of ADE and BDEC (ADE / BDEC). You can safely assume that the given triangle is a valid triangle with positive area.

Output

For each case of input you have to print the case number and AD. Errors less than 10-6 will be ignored.

Sample Input	Output for Sample Input
4 100 100 100 2 10 12 14 1 7 8 9 10 8.134 9.098 7.123 5.10	Case 1: 81.6496580 Case 2: 7.07106781 Case 3: 6.6742381247 Case 4: 7.437454786

 

题意：知道三条边，面积比求AD的长。

题解：根据相似三角形性质就ok啦！

AC代码：

#include<cstdio>
#include<cmath>
#include<cstring>
#include<algorithm>
using namespace std;
#define INF 0x3f3f3f3f
#define CLR(a,b) memset(a,b,sizeof(a))
int main()
{
int u,ca=1;
scanf("%d",&u);
while(u--)
{
double a,b,c,k;
scanf("%lf%lf%lf%lf",&a,&b,&c,&k);
k=k/(k+1);
k=sqrt(k);
printf("Case %d: %.8lf\n",ca++,k*a);
}
return 0;
}