Leetcode 240. Search a 2D Matrix II (Medium) (cpp)
2016-08-22 16:43
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Leetcode 240. Search a 2D Matrix II (Medium) (cpp)
Tag: Binary Search, Divide and Conquer
Difficulty: Medium
/*
240. Search a 2D Matrix II (Medium)
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
For example,
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5, return true.
Given target = 20, return false.
*/
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
int r = matrix.size() - 1, c = matrix[0].size() - 1;
int i = 0, j = c;
while (i <= r && j >= 0) {
if (matrix[i][j] > target) j--;
else if (matrix[i][j] < target) i++;
else return true;
}
return false;
}
};
Tag: Binary Search, Divide and Conquer
Difficulty: Medium
/*
240. Search a 2D Matrix II (Medium)
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
For example,
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5, return true.
Given target = 20, return false.
*/
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
int r = matrix.size() - 1, c = matrix[0].size() - 1;
int i = 0, j = c;
while (i <= r && j >= 0) {
if (matrix[i][j] > target) j--;
else if (matrix[i][j] < target) i++;
else return true;
}
return false;
}
};
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