Runaround Numbers_usaco2.2.3_预处理+二分

题目描述 Description

循环数是那些不包括0且没有重复数字的整数(比如81362)并且还应同时具有一个有趣的性质, 就像这个例子:

如果你从最左边的数字开始(在这个例子中是8)向右数最左边这个数(如果数到了最右边就回到最左边),你会停止在另一个新的数字(如果停在一个相同的数字上，这个数就不是循环数).就像: 8 1 3 6 2 从最左边接下去数8个数字: 1 3 6 2 8 1 3 6 所以下一个数字是6

重复这样做 (这次从“6”开始数6个数字) 并且你会停止在一个新的数字上: 2 8 1 3 6 2, 也就是2

再这样做 (这次数两个): 8 1

再一次 (这次一个): 3

又一次: 6 2 8 这时你回到了起点,在经过每个数字一次后回到起点的就是循环数。如果你经过每一个数字一次以后没有回到起点, 你的数字不是一个循环数。

给你一个数字 M (在1到9位之间), 找出第一个比 M大的循环数, 输出数据保证结果能用一个无符号长整型数装下。

输入描述 Input Description

仅仅一行, 包括M

输出描述 Output Description

仅仅一行，输出第一个比M大的循环数。

题解 Analysis

打表大法好！！！

预处理一下打个457的表再二分第一个比n大的循环数

最坏情况找logn2也就是9次，谜一般的速度

源程序 Code

/*
ID:wjp13241
PROG:runround
LANG:C++
*/
#include <stdio.h>
using namespace std;
int t[457]={1,2,3,4,5,6,7,8,9,13,15,17,19,31,35,37,39,51,53,57,59,71,73,75,79,91,93,95,97,147,174,258,285,417,471,528,582,714,741,825,852,1263,1267,1623,1627,2316,2356,2396,2631,2635,2639,2671,2675,2679,2716,2756,2796,3126,3162,3526,3562,3926,3962,5263,5267,5623,5627,6231,6235,6239,6271,6275,6279,6312,6352,6392,6712,6752,6792,7126,7162,7526,7562,7926,7962,9263,9267,9623,9627,12368,12746,12796,12863,13628,13678,13849,13894,16274,16279,16724,16729,17246,17296,17368,17863,18349,18394,18623,18673,23186,23479,23681,23974,24167,24617,24739,24789,27416,27461,27916,27961,28136,28479,28631,28974,29167,29617,29734,29784,31286,31786,31862,31867,34297,34792,34918,34968,36281,36781,36812,36817,38491,38496,38941,38946,39247,39418,39468,39742,41389,41627,41672,41839,42397,42897,42973,42978,46127,46172,46389,46839,47392,47892,47923,47928,49138,49183,49638,49683,61274,61279,61724,61729,62318,62741,62791,62813,63128,63178,63849,63894,67241,67291,67318,67813,68123,68173,68349,68394,72416,72461,72916,72961,73186,73429,73681,73924,74162,74239,74289,74612,78136,78429,78631,78924,79162,79234,79284,79612,81236,81362,81367,81736,83491,83496,83941,83946,84297,84792,84913,84963,86231,86312,86317,86731,89247,89413,89463,89742,91384,91627,91672,91834,92347,92473,92478,92847,94138,94183,94638,94683,96127,96172,96384,96834,97342,97423,97428,97842,134259,134859,142359,142953,148359,148953,194253,194853,235914,235974,253194,253794,259134,259734,295314,295374,314295,314895,319425,319485,342591,342597,348591,348597,359142,359148,359742,359748,374295,374895,379425,379485,423591,423597,425319,425379,425913,425973,429531,429537,483591,483597,485319,485379,485913,485973,489531,489537,531429,531489,531942,531948,537429,537489,537942,537948,591342,591348,591423,591483,597342,597348,597423,597483,734259,734859,742359,742953,748359,748953,794253,794853,835914,835974,853194,853794,859134,859734,895314,895374,913425,913485,914235,914835,942531,942537,948531,948537,953142,953148,953742,953748,973425,973485,974235,974835,1246895,1248596,1249568,1258946,1426958,1496258,1526894,1596824,1824956,1842695,1849625,1894256,1942568,1946825,1948526,1958246,2415968,2461958,2468951,2485961,2495618,2495681,2518496,2519468,2561894,2568194,2581496,2589461,2619485,2689415,2695184,2695814,4152689,4159682,4256189,4256819,4269518,4269581,4612589,4619582,4682519,4689512,4852619,4859612,4956182,4956812,4962518,4962581,5124689,5184269,5184962,5194682,5261948,5268941,5618249,5618942,5681249,5681942,5814269,5814962,5824619,5894612,5961248,5968241,6124859,6125894,6182495,6189425,6194852,6195824,6251849,6258149,6812495,6819425,6824159,6825194,6894152,6895124,6951842,6958142,8124956,8142695,8149625,8194256,8241596,8246195,8249561,8251946,8426951,8496251,8526194,8596124,8941526,8942561,8946125,8951246,9415268,9425618,9425681,9461258,9468251,9485261,9512468,9518426,9561824,9568124,9581426,9582461,9612485,9625184,9625814,9682415};
int find(int x)
{
int l=0,r=456,v;
while (l<=r)
{
int mid=(l+r)>>1;
if (t[mid]>x)
{
v=t[mid];
r=mid-1;
}
else
l=mid+1;
}
return v;
}
int main()
{
freopen("runround.in","r",stdin);
freopen("runround.out","w",stdout);
int n;
scanf("%d",&n);
printf("%d\n",find(n));
fclose(stdin);
fclose(stdout);
return 0;
}